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Algebra

Chapter 15

Problem 1

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The surface area of a geometric solid is the total area
of all the exposed surfaces of the geometric solid.

The lateral surface area of any right solid is the area of
the side surfaces between the bases.

Given: a = cm,   b = cm,   and c = cm,  

(a) The lateral surface area of the figure immediately above Aa = cm2


Example:

Given: the figure shown above with
Length a = 9 in
Length b = 12 in
Length c = 14 in
Length d = 11 in

Find the surface area.
The surface area is 2 times the area of the face plus the 3 rectangular surface areas.

Thus, the total surface area can be written as As = (ab + cd + bd + ad) in2

Substituting values gives: As = (9in)(12in) + (14in)(11in) + (12in)(11in) +(9in)(11in)

So: As = 493 in2

This can be solved using the graphing calculator by entering 9*12 + 14*11 + 12*11 + 9*11
into the Function f(x)= box, then click on the Plot Graph button.
The answer will appear below the Function f(x)= box as f(x) = 493.