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Algebra
Chapter 22
Problem 1
Select a different problem
Example:
Solve for x: Given the equation
Solution: First, to solve for x you need to put all the terms with x
in them on the left side of the equal sign. This is already done for this example.
Second, put all the constant terms on the right hand side of the equal
sign. This can be done by subtracting
1/
6 from both sides of the equality. This
gives you
(subtracting
1/
6 from both sides of the equality
maintains equality) You now have all x terms (the variable) on the left side
and all the constant terms on the right side. Third, multiply all the terms on
both sides of the equal sign by the least common muktiple which is (3)(3)(2) = 18. This gives you
12x = -3 + 10 = 7
Your goal was to solve for x. This can be done by dividing both sides of the
equality by 12 (to maintain equality and to solve for x). When you do this you get
All algebra solutions can be checked for correctness by substituting the root
back into the original given equation. To do this here, you substitute x = 0.5833... into
everywhere there is and x. This gives you
 +\frac{1}{6} = \frac{5}{9})
so: 0.38888...+ 0.166666...= 0.5555...
which is :
0.5555... = 0.5555... which is true...thus x = 0.5833... is the correct solution (root)!!
