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Algebra_2
Chapter 37
Problem 1
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Above the surface of the earth, an object that is thrown downward toward the earth
with an initial velocity of
 \frac{m}{s})
will increase its velocity due to gravity at an accelerated
rate of
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for every second.
The shorthand form that describes the velocity of this object
at some time t is
 = (v(0) + at) \frac{m}{s})
.
This function v(t) is graphed below for the initial velocity v(0)=2m/s and for the acceleration a=9.8m/s/s.
(Note: at time t=0s the velocity v(0) = 2m/s and at time t=2s the velocity v(2) = 21.6m/s as shown to
the left on the vertical axis).
Check several values of time t to find the corresponding v(t) on the left axis.