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Algebra_2
Chapter 41
Problem 5
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The perimeter of a rectangular lot is given as P = 56 m.
The longer length of the lot is L = 18 m.
The perimeter equals twice the length plus twice the width of the lot or
.
The shorter length of the lot is
.
Solving for the area of the lot
m
2.
Thus, for P = 56 m and L = 18 m, enter
18(56-2(18))/2 in the Function f(x) box and click on the Plot Graph box
the answer will appear to the right of f(x) = 180.
Note the parentheses that are needed.
Thus you can check your calculations with this Graphing Calculator.
