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Algebra_4

Chapter 84

Problem 5

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Note: Give your answers in decimal form out to 6 decimal points.

Find four consecutive integers such that
times the sum of the first and third
is greater than times the second.

The four consecutive integers are


N =



N + 1 =



N + 2 =



N + 3 =




Example:
Find three consecutive integers such that the sum of
the first and third is 146.

Solution: Assign the consecutive integers as:
N, N + 1, and N + 2

The sum of the first integer and the third integer is 146, so you write
N + N + 2 = 146
Adding N's and subtracting 2 gives
2N = 144
Dividing by 2 solves for N
so N = 72

The consecutive integers are 72, 73, and 74.