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Algebra_4

Chapter 95

Problem 1

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Note: To get credit, also enter your units as 2.1*(f/s) (feet per second),
6.4*(k/h) (kilometers per hour), 7.82*(m/h) (miles per hour),
9.95*(m/s) (meters per second), etc...Round your answer to two
decimal points. Do not show the trailing zero, that is 2.40 becomes 2.4.


Given:
In the morning John made the trip in hours. In the
afternoon Bill made the same trip in hours. Find the
velocity of each if the velocity of Bill was miles per
hour less than the velocity of John. (Remember to enter your units)

(a) vj (vel of John) =

(b) vb (vel of Bill) =


Example:

In the morning the passenger train made the trip in 3 hours
In the afternoon the freight train made the same trip in 7 hours.
Find the velocity of each if the velocity of the freight train
was 40 miles per hour less than the velocity of the passenger train.

In shorthand form the problem can be written as follows:
Freight train time tf = 3 hours. (1)
Passenger train time tp = 7 hours
The difference in velocities vp = vf + 40 (2)
Since they traveled the same distance, vftf = vptp (3)
Substituting equation (2) into equation (3) gives
vftf = (vf +40)tp
or vf(tf - tp) = 40tp
Thus, the velocity of the freight train vf = 40tp/(tf - tp)
So The velocity of the freight train vf = 40(3)/(7 - 3) = 30 miles per hour
and the velocity of the passenger train vp = 30 + 40 = 70 miles per hour