You have not paid for this chapter
Physics
Chapter 1
Problem 1
Select a different problem
(a) A car is traveling at a constant velocity of 5 m/s. How far will it travel in 15 seconds?
Example:
(a) An object is traveling at a velocity of 10.25 m/s. How far will it travel in 4 seconds?
(b) If another object has a mass of 10 kilograms, and a force of 200 newtons acting on it, what will the acceleration of this object be?
(a) Review: The velocity(v) of an object is directly proportionsl to the distance(d) the object travels
and inversely proportional to time(t) it travels. This can be written mathematically as v = d / t.
This can be solved for the distance as d = v * t.
We are given the constant velocity(v) of a given object. For a given time(t) period
we wish to find the distance(d) the object will travel.
From the distance equation above, distance(d) = velocity(v) * time(t), thus we calculate distance
to be d = v * t, or, d = 10.25 * 4 = 41 meters. (Note how the units of time cancel.)
(b) Review: The acceleration(a) of an object is directly proporional to the force(F) acting on the object
and inversely proportional to the mass(m) of the object. This can be written mathematically as a = F / m.
We are given the constant force acting on a given object. For a given mass of the object
we wish to find the acceleration of the object.
From the acceleration equation above, acceleration(a) = force(F) / mass(m), we calculate the
acceleration a = F / m, or a = 200 / 10 = 20 m / sec^2. (Note how the units of mass cancel.)
To solve (a) using the graphing calculator below, enter 10.25*4 in the Function f(x)=box
then click on the Plot Graph button.
The answer will appear as f(x)=41 below the Function f(x)=box.
To solve (b) using the graphing calculator below, enter 200/10 in the Function f(x)=box
then click on the Plot Graph button.
The answer will appear as f(x)=20 below the Function f(x)=box.
