You have not paid for this chapter
Physics
Chapter 1
Problem 2
Select a different problem
(a) A car is traveling at a constant velocity of 5 m/s. How far will it travel in 15 seconds?
Example:
(a) An object is traveling at a velocity of 10.25 m/s. How far will it travel in 4 seconds?
(b) If another object has a mass of 10 kilograms, and a force of 200 newtons acting on it, what will the acceleration of this object be?
(a) Review: The velocity(v) of an object is directly proportionsl (numerator) to the distance(d) the object travels
and inversely proportional (denominator) to time(t) it travels. This can be written mathematically as v = d / t.
This can be solved for the distance as d = v * t.(multiply both sides by t)
We are given the constant velocity(v) of a given object. For a given time(t) period
we wish to find the distance(d) the object will travel.
From the distance equation above, distance(d) = velocity(v) * time(t), thus we calculate distance
to be d = v * t, or, d = 10.25 * 4 = 41 meters. (Note how the units of time cancel.)
(b) Review: The acceleration(a) of an object is directly proporional (numerator) to the force(F) acting on the object
and inversely proportional (denominator) to the mass(m) of the object. This can be written mathematically as a = F / m.
We are given the constant force acting on a given object. For a given mass of the object
we wish to find the acceleration of the object.
From the acceleration equation above, acceleration(a) = force(F) / mass(m), we calculate the
acceleration a = F / m, or a = 200 / 10 = 20 m / sec^2. (Note how the units of mass cancel.)
To solve (a) using the graphing calculator below, enter 10.25*4 in the Function f(x)=box
then click on the Plot Graph button.
The answer will appear as f(x)=41 below the Function f(x)=box.
To solve (b) using the graphing calculator below, enter 200/10 in the Function f(x)=box
then click on the Plot Graph button.
The answer will appear as f(x)=20 below the Function f(x)=box.
